Question

Please friends solve question no. 29

Answer 1

square of length of an arm of square=
$(12 \sqrt{2} ) {}^{2} \div 2$
=144
so the length of the arm of square is
$\sqrt{144 } = 12$
then the peremeter of both is 12.4=48 cm
length of tangle arm=48/3=16
height of tarangle=root 16^2+8^2
=root 320
now area of tanngle=1/2.16.root 320