Please friends solve this : -
If abc = 1, then show that
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Answers
Answered by
5
Hey!!
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given case, abc = 1
=> 1/(1+a+1/b) + 1/(1+b+1/c) + 1/(1+c+1/a)
=> 1/(1+a+ac) + 1/(c + bc + 1)/c + 1/(a + ac + 1)/a , (as abc = 1, hence ac = 1/b)
=> 1/(1+a+ac) + c/(1+c+bc) + a/(1+a+ac) ,
=>(1+a)/(1+a+ac) + ac/(a + ac + abc) , (multiplying and dividing ‘a’ to the second term.
=> (1 + a)/(1+a+ac) + ac/(1+a+ac);
=> (1+a+ac)/(1+a+ac)
=> 1
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I Hope It's Help You.....!!!!!
please tick the brainliest answer.
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given case, abc = 1
=> 1/(1+a+1/b) + 1/(1+b+1/c) + 1/(1+c+1/a)
=> 1/(1+a+ac) + 1/(c + bc + 1)/c + 1/(a + ac + 1)/a , (as abc = 1, hence ac = 1/b)
=> 1/(1+a+ac) + c/(1+c+bc) + a/(1+a+ac) ,
=>(1+a)/(1+a+ac) + ac/(a + ac + abc) , (multiplying and dividing ‘a’ to the second term.
=> (1 + a)/(1+a+ac) + ac/(1+a+ac);
=> (1+a+ac)/(1+a+ac)
=> 1
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I Hope It's Help You.....!!!!!
please tick the brainliest answer.
ArchitectSethRollins:
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Answered by
1
Answer:
1 will be the answer
Step-by-step explanation:
it took too much time to solve me
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