Question

please friends solve this one...

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

Given,

ax³+3x²-3 and 2x³- 5x+a

when divided by x-4

to find out the remainder

put x=4 in the polynomial

f(4) = ax³+3x²-3

f(4) = a(4)³+3(4)²-3

= 64a+ 48-3

R1 = 64a+ 45......(i)

f(4)= 2x³- 5x+a

= 2*4³- 5(4)+a

= 128-20+a

R2 = 108+a........ii

1) R1 = R2

64a+ 45 = 108+a

64a-a = 108-45

63a = 63

a= 1

2) R1+R2 = 0

64a+ 45+ 108+a = 0

65a+ 153 = 0

65a= 153

a= 153/65

Similarly you can put the value of R1 and R2 in the 3) equation.