Math, asked by annu08143, 6 hours ago

please get help me fast if anybody know the answers of these parts..​

Attachments:

Answers

Answered by PRABEERPATIL
0

Answer:

Correct option is

D

i)

4

1

and ii)

9

1

1 2 3 4 5 6

1 (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

2 (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

3 (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

4 (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

5 (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

6 (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

(i) Let the event that the number of each die is even.

Favourable outcomes ={(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)}

Probabaility that number on each dice is even =

36

9

=

4

1

(ii) That the sum of numbers appearing on the two dice is 5.

Favourable outcomes ={(1,4),(2,3),(3,2),(4,1)}

Probability that the sum of the numbers apperaing on the two dice is 5=

36

4

=

9

1

Similar questions