Question

Please get me this answer asap please

Answer 1

Let a , d are first term and

common difference of an A.P.

according to the problem given,

9th term = 499

=> a + 8d = 499 ---( 1 )

499th term = 9

=> a + 498d = 9 ----( 2 )

Subtract (1) from (2), we get

490d = -490

=> d = (-490)/490 = -1

Substitute d = 1 in equation

(1) , we get

a + 8(-1) = 499

=> a = 499+8

=> a = 507

Now ,

Let n th term of A.P = 0

=> a + (n-1)d = 0

=> 507 + (n-1)×(-1) = 0

=> (n-1)= (-507)/(-1)

=> n -1 = 507

=> n = 507+1

=> n = 508

Therefore,

508 the term in given A.P is

zero.

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