Question

please give a answer

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Answer 1

$\huge\boxed{\mathcal{\pink{\fcolorbox{red}{purple}{ Solution }}}}$

❥ tan ( A + B ) = √3 and tan ( A - B ) = 1/√3

➡ tan ( A + B ) = tan 60°

➡ tan ( A - B ) = tan 30°

{ A + B = 60 ° --------- i

{ A - B = 30 ° ---------ii

$\underline\bold\green{From\:eq\:(i)\:and\: (ii)}$

➡ A + B = 60 °

➡ A - B = 30°

➡ 2A = 90 °

➡ A = 45 °

$\underline\bold\green{Putting\:The\: Value\:eq-(ii) }$

➡ A - B = 30 °

➡ 45 - B = 30 °

➡ - B = 30 ° - 45 °

➡ - B = - 15

➡ B = 15

Tha value Of A = 45 ° & B = 15

Answer 2

Given:

• tan (A+B) =√3

• tan(A-B) = 1/√3

To find :

• A and B :

Solution:

$\implies \tan \: (A+B) = \sqrt{3} \\ \\ \implies \: \tan \: (A+B) = \tan \: 60 \degree \\ \\ \implies \: (A+B) = 60 \degree \: - - - - - (1)$

and

$\implies \: \tan \: (A - B) = \frac{1}{ \sqrt{3} } \\ \\ \implies \tan \: (A - B) = \tan \: 30 \degree \\ \\ \implies \: (A - B) = 30 \degree \: - - - - - (2)$

• Add both equation 1 and 2 we get ,

=>2A = 90°

=> A= 90°/2

=> A = 45 °

now put the value of A in equation 1 we get ,

=> A+B = 60°

=> B= 60°-45°

=> B= 15°

Hence, the value of A is 45 ° and B is 15°