Question

please give a answer of this question​

Answer 1

answer is in the attachment

Answer 2

$a = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \: and \: b = \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

$a = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

$\: \: \: \: \: \: \: = \frac{ {( \sqrt{3} + \sqrt{2} )}^{2} }{3 - 2}$

$\: \: \: \: \: = 3 + 2 \sqrt{6} + 2$

$\: \: \: \: \: = 5 + 2 \sqrt{6}$

$b = \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

$\: \: \: \: \: = \frac{ {( \sqrt{3} - \sqrt{2}) }^{2} }{3 - 2}$

$\: \: \: \: \: = 3 - 2 \sqrt{6 } + 2$

$\: \: \: \: \: = 5 - 2 \sqrt{6}$

${a }^{2} + {b}^{2} = {(5 + 2 \sqrt{6} )}^{2} + {(5 - 2 \sqrt{6} )}^{2}$

$\: \: \: \: \: \: \: \: \: \: = 25 + 2.5.2 \sqrt{6} + 24 + 25 - 2.5.2 \sqrt{6} + 24$

$\: \: \: \: \: \: \: \: \: \: = 2(25 + 24)$

$\: \: \: \: \: \: \: \: \: \: = 2 \times 49$

$\: \: \: \: \: \: \: \: \: \: = 98$