Question

please give a answer this question☝☝☝​

Answer 1

Let r1and r2 Inner and outer radii of cylindrical pipe

r1= 4/2 cm = 2cm

r2= 4.4/2 cm = 2.2 cm

Height of cylindrical pipe, h = length of cylindrical pipe = 77 cm

(i)curved surface area of outer surface of pipe = 2πr1h

= 2 × 22/7 × 2 × 77 cm2

= 968 cm2

(ii) curved surface area of outer surface of pipe = 2πr2h

= 2 × 22/7 × 2.2 × 77 cm2

= (22×22×2.2) cm2

= 1064.8 cm2

(iii) Total surface area of pipe = inner curved surface area + outer curved surface area + Area of both circular ends of pipe.

=2πr1h + 2πr2h + (r22-r21)
= 2038.08 cm2

Therefore, the total surface area of the cylindrical pipe is 2038.08 cm2.

Hope it helped!