Question

Please give a clear cut explanation​

Answer 1

☆Points to note before solving:

1. draw the free body diagram of given system.
2. only single string is present, so same tension throughout and the blocks will also have the same acceleration.
3. F_(net) = F_(driving) – F_(opposing) = ma

☆Solution

For 40 kg block

$\ 40gsin30\degree - T = 40a$

$\ 20g - T = 40a$ ---------(1)

For 30 kg block

$\ T - 30gsin30\degree = 30a$

$\ T - 15g = 30a$ ----------(2)

•Adding equation 1 and 2

20g - 15g = 70a

$\rightarrow\sf a = \dfrac{5g}{70}$

• Now, put the value of 'a' in 2nd eq.

$\sf T - 15g = 30\times \dfrac{5g}{70}$

$\sf T - 15g = \dfrac{15g}{7}$

$\sf T = \dfrac{15g}{7} + 15g$

$\sf T = (\dfrac{15}{7} + 15)g$

$\sf T = \dfrac{120}{7}9.8$

$\sf T = 120\times 1.4$

$\bf T = 168\: N$ ----☆

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Answer 2

Answer:

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