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Cos 3$ = sin 2$
Therefore
Sin(90 - 3$) = sin 2$
i. e.
90 - 3$ = 2$
5$ = 90
[$ = 18]
Here I've used $ in place of theta
Therefore
Sin(90 - 3$) = sin 2$
i. e.
90 - 3$ = 2$
5$ = 90
[$ = 18]
Here I've used $ in place of theta
Answered by
4
Hello,
cos 3θ=sin 2θ
we know that:
sin θ = cos (90°-θ)
so:
cos 3θ= sin2θ;
cos 3θ=cos (90°-2θ) ;
3θ=90°-2θ;
3θ+2θ=90°;
5θ=90°
θ=90/5=18°
then
θ=18°
bye :-)
cos 3θ=sin 2θ
we know that:
sin θ = cos (90°-θ)
so:
cos 3θ= sin2θ;
cos 3θ=cos (90°-2θ) ;
3θ=90°-2θ;
3θ+2θ=90°;
5θ=90°
θ=90/5=18°
then
θ=18°
bye :-)
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