Math, asked by john44, 1 year ago

please give a very clear explanation dont use any shortcut

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Answered by abhi178
1
let A do work in x days and B do work in y days .

we know,
both work together in (xy)/(x + y) days

hence,
xy/(x + y) = 8 days


now both start work together and after 6 days A left the work .

both do work within 6 days ,

hence,
both do 6/8 part of work in 6days .
rest (1-6/8) part of work doing by only B

hence, 1/4 part of work do by B in 6 days
hence, complete work do by B in 6 x 4 =24 days.

but B do complete work in y days .
so, y = 24 days

24x/(24+x) = 8

3x. = 24 + x

x = 12 days






john44: thanks a lot in advance
abhi178: if A does work in x days and B does work in y days ,
abhi178: it means A do in 1 day 1/x part
abhi178: same way y do in 1 day 1/y part of work
abhi178: both will do work together in one days = (1/x + 1/y ) part of work
john44: thanks
abhi178: so, A and B both will do complete work 1/(1/x + 1/y) =xy/(x + y)
abhi178: thanks for your complement
abhi178: i thinks now you have to understand ,
john44: hmmm
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