Math, asked by Anonymous, 4 months ago

please give all answer​

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Answered by ashwathy39
0

Answer:

The ratio of distance travelled and the time taken by a body can be zero but not negative.

Since distance and time are positive quantities and speed is obtained by the ratio of these two quantities, speed cannot be negative.

Answered by hharshit493
2

(6) The ratio of distance travelled and the time taken by a body can be zero but not negative. Since distance and time are positive quantities and speed is obtained by the ratio of these two quantities, speed cannot be negative.

(7) When an object is speeding up, the acceleration is in the same direction as the velocity. Thus, this object has a positive acceleration. In Example B, the object is moving in the negative direction (i.e., has a negative velocity) and is slowing down.

(8) "Displacement" is the quantity which is measured by the area occupied under the velocity time graph distance.15-May-2020

(9)The simplest type of motion (excluding the trivial case in which the body under investigation remains at rest) consists of motion with constant velocity. This type of motion occurs in everyday life whenever an object slides over a horizontal, low friction surface: e.g., a puck sliding across a hockey rink.

(10)The condition in which a body covers equal distance in an equal interval of the time is known to be uniform velocity. In equation( d=v t ) v is the average velocity of a body during time t. if both its magnitude and direction do not change with time then it can be said that the body is at uniform velocity.

(11) vf= vi + at

0 = vi - 2.5 + (-10)

vi =25ms

(12)When a stone is thrown vertically upwards, it has some initial velocity (letu). As the stone goes its velocity goes on decreasing (v it is moving against the gravity) and at the highest point i.e., maximum height) its velocity become zero. Let the stone takes time 't' second to reach at the highest point.

(13) Intainal speed of airplane u= 0 m/s

Accerraltion of plane a= 3.2 ms^2 and

timetaken 38.8 s

using formula, distance coveredS = ut + 1/2at^2

=)) S=0+32.8)+0.5(3.2)(32.8)^2

= 1721.3 ~ 1720m

(14) and (15) Don't no?

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