Question

please give answer......​

Answer 1

Answer:

c) 2$\sqrt{2}$

Step-by-step explanation:

Given equation  $\sqrt{2}$$x^2$ - 4x + 6 = 0

Here , a = $\sqrt{2}$; b= -4 ; c= 6

We know that sum of roots of a quadratic equation = -b/a

= -(-4)/$\sqrt{2}$

= 4/$\sqrt{2}$

= 2$\sqrt{2}$

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Answer 2

Answer:

Answer:

c) 2\sqrt{2}

2

Step-by-step explanation:

Given equation \sqrt{2}

2

x^2x

2

- 4x + 6 = 0

Here , a = \sqrt{2}

2

; b= -4 ; c= 6

We know that sum of roots of a quadratic equation = -b/a

= -(-4)/\sqrt{2}

2

= 4/\sqrt{2}

2

= 2\sqrt{2}

2

Hope you find this useful. Please rate the answer!