Math, asked by ItzHackerAryan, 7 months ago

please give answer..​

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Answered by Anonymous
1

Answer:

(\frac{10}{9} a^5b^6c^6)(\frac{-3}{2} b^2c)(\frac{6}{5} c^3d^4)(-a^3d^5)\\\\= \frac{10*-3*6}{9*2*5} (-a^8b^8c^{10}d^9)\\\\

= \frac{-180}{90}(-a^8b^8c^{10}d^9)\\=-2(-a^8b^8c^{10}d^9)\\=2a^8b^8c^{10}d^9

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