Question

please give answer do it very fast ​

Answer 1

Given, AB = 8 m, BC = DC = 5 m

AE = DC

AE = 5 m

AB - AE = BE

8 - 5 = BE

BE = 3 m

Now, in triangle BEC,

By Pythagoras theorem,

${BC} ^{2}$ = ${EC} ^{2}$ + ${BE} ^{2}$

25 = ${EC} ^{2}$ + 9

${EC} ^{2}$ = 25 - 9

${EC} ^{2}$ = 16

EC = 4 m

Now, Area of rectangle AECD,

Length * Breadth = 4* 5 = 20 ${m} ^{2}$

Now, Area of right triangle BEC = 1/2 * base * height

$\implies{1/2*\: 3*\:4}$

$\implies{6}$ ${m} ^{2}$

Finally, Area of quadrilateral = ( 20 + 6 ) ${m} ^{2}$

⚫Area of quadrilateral = 26 ${m} ^{2}$

⚫Option C) is correct.