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In triangle AEB and Triangle DEC,
ang A= ang D=90 ,
and , ang E = angE ( COMMON) ,
SO , AEB IS SIMILAR TO DEC ,
:., AE/ DE= BE/ CE
SO , AE×CE = BE × DE
PROVED.
ang A= ang D=90 ,
and , ang E = angE ( COMMON) ,
SO , AEB IS SIMILAR TO DEC ,
:., AE/ DE= BE/ CE
SO , AE×CE = BE × DE
PROVED.
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