Question

please give answer fast​

Answer 1

Answer:

angle A = 30 degree

angle B = 125degree

angle c= 25 degree

Answer 2

$\boxed{\huge{\bold{\red{\mathfrak{Question:}}}}}$

$\red{\textsf{In a ΔABC, \angle A + \angle B = 125\degree and \angle B + \angle C = 150\degree .}}$

$\red{\textsf{ Find all the angle of ΔABC.}}$

$\boxed{\huge{\bold{\red{\mathfrak{Solution:}}}}}$

$\boxed{\blue{\mathsf{\because \angle A + \angle B = 125\degree}}}$

$\blue{\mathsf{\therefore \angle B = 125\degree - \angle A \: ......(i)}}$

$\large{\green{\mathrm{Also,}}}$

$\boxed{\blue{\mathsf{ \angle B + \angle C = 150\degree \: .......(ii)}}}$

$\green{\textsf{Putting value of eq^n (i) in eq^n (ii), We get,}}$

$\blue{\mathsf{\therefore 125\degree - \angle A + \angle C = 150\degree}}$

$\blue{\mathsf{\implies \angle C - \angle A = 150\degree - 125\degree}}$

$\sf \blue{\implies \angle C - \angle A = 25\degree}$

$\sf \blue{\implies \angle C = \angle A + 25\degree .......(iii)}$

${\green{\textsf{As we know that,}}}$

$\large{\boxed{\green{\textsf{Sum of all angles of a Δ = 180°}}}}$

$\large{\red{\textrm{Therefore,}}}$

$\therefore \rm \blue{\angle A + \angle B + \angle C = 180\degree}$

$\green{\textsf{From eq^n (i) and eq^n (iii), We get,}}$

$\rm \blue{\therefore \angle A + 125\degree - \angle A + \angle A + 25\degree = 180\degree}$

$\rm \blue{\implies \angle A + 125\degree \cancel{- \angle A} \cancel{+ \angle A} + 25\degree = 180\degree}$

$\rm \blue{\implies \angle A + 150\degree = 180\degree}$

$\rm \blue{\implies angle A = 180\degree - 150\degree}$

$\implies \rm \bf \boxed{ \blue{\angle A = 30\degree}}$

$\large{\green{\textrm{Now,}}}$

$\because \rm \red{\angle B = 125\degree - \angle A}$

$\green{\textsf{Hence, \angle A = 30\degree }}$

$\therefore \rm \blue{\angle B = 125\degree - 30\degree}$

$\implies \rm \bf \boxed{\blue{\angle B = 95\degree}}$

$\large{\green{\textrm{Also,}}}$

$\because \rm \red{\angle C = \angle A + 25\degree}$

$\green{\textsf{Hence, \angle A = 30\degree }}$

$\therefore \rm \blue{\angle C = 30\degree + 25\degree}$

$\implies \rm \bf \boxed{\blue{\angle C = 55\degree}}$

$\bold{\green{\textsf{Hence, all angles of ΔABC are}}}$

$\bold{\green{\mathsf{30\degree, \: 95\degree \: and \: 55\degree}}}$