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answer is 25 sq cm
Step-by-step explanation:
A[triangle CDE] = 20 sq cm
let us assume BD = x
BC = BD+ DC
x + 2x
=3x
in triangle ABC and triangle CDE ,
angle CAB = angle CED
angle CBA = angle CDE
by corresponding angle test
triangle ABC and triangle CDE are similar [ by AA test of similarity]
A[triangle ABC ] / A[triangle CDE] = BC^2 / DC^ 2 = 3x^2 / 2x^2 = 9 / 4
A [ triangle ABC ] = 9/4 A[triangle CDE ] = 9/4 x 20
= 45
A [ ABDE ] = A [ ABC] - A [ CDE ]
=45 - 20
= 25 SQ CM
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