Question

please give answer for the above​

Answer 1

Explanation:

'l = ("dq")/("dt") = "dq" = "l"d"t"

Hence the area under the l-t curve gives charge flown

Area of the l-t curve(as given in the question) = 1/2 × 2×1/2 = 0.5

total charge passed through the loop = 0.5C

Now we know,

R = 1/2 × 10 = 5Wb

charge in magnetic flux through the loop = 5Wb

5 = B(0.001)

B = 5000T

the magnitude of the field applied = 5000 T