Question

please give answer in detail of 10 question

Answer 1

Here your answer goes

Step :-1

Given ,

$D_{1} = 16cm$

$D_{2} = 12cm$

Where , D is a Diagonal of Rhombus

Step :-2

We know that when half of the diagonal meet at  a point then they in -closes a triangle

By Pythagoras theorem find its side :-

$\frac{16}{2}=8cm$

$\frac{12}{2}=6cm$

Step :- 3

Let x be the side of the rhombus

$x^2 = P^2 + B^2\\x^2 =( 8^2 + 6^2 )cm^2\\x^2 = ( 64 + 36 ) cm^2\\x^2 = 100 cm^2\\x = \sqrt{100}\\x = 10cm$

Step :- 4

Perimeter of rhombus = 4 * Side

⇒ 4 * x

⇒ 4 * 10

⇒ 40 cm

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