Question

Please give answer in explanation
$are \: there \: rational \: numbers \: \frac{2}{3} \: \frac{4}{6} \: \frac{6}{9} \: \frac{8}{12} \: \frac{ - 10}{ - 15} \: \frac{ - 42}{ - 63} \: \\ equivalent \: and \: how$
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Answer 1

Answer:

Yaa all are equivalent

$\frac{4}{6} \div \frac{2}{2} = \frac{2}{3} \\ \frac{6}{9} \div \frac{3}{3} = \frac{2}{3} \\ \frac{8}{12} \div \frac{4}{4} = \frac{2}{3} \\ \frac{ - 10}{ - 15} here \: minus \: minus \: cut \\ so \frac{10}{15} \div \frac{5}{5} = \frac{2}{3} \\ here \: also \: minus \: cut \\ so \frac{42}{63} \div \frac{21}{21} = \frac{2}{3}$

So all are equivalent

Please mark as brainliest

Answer 2

Step-by-step explanation:

$hola$

$good \: afternoon$

$\frac{4}{6} = \frac{2}{3}$

$\frac{6}{9} = \frac{2}{3}$

$\frac{8}{12} = \frac{2}{3}$

$\frac{ - 10}{ - 15} = \frac{2} {3}$

$\frac{ - 42}{ - 63} = \frac{ 2}{ 3}$

$all \: are \: equal \: to \: \frac{2}{3} so \: these \: are \: equivalent.$

$it \: is \: your \: answer \:bro$

$thanks$

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