Physics, asked by deepakdodiya2004, 6 months ago

please give answer it is important for me ​

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Answers

Answered by sreeh123flyback
1

Explanation:

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deepakdodiya2004: thanks bro you are so helping
sreeh123flyback: welcome are you a JEE student or in class 11
Answered by Anonymous
11

Explanation :

\green{  \displaystyle \int \tt  \dfrac{ \sqrt[5]{x {}^{2} } }{ \sqrt{x {}^{ \dfrac{14}{5} } }} dx} \\  \\  \\  \displaystyle \longrightarrow  \tt\int  \dfrac{ \bigg(x {}^{2} \bigg) {}^{  \dfrac{1}{5} } }{  \bigg(x {}^{ \dfrac{14}{5}} \bigg) {}^{ \dfrac{1}{2} } } dx \\  \\  \\ \displaystyle \longrightarrow  \tt\int   \dfrac{x {}^{ \dfrac{2}{5} } }{x {}^{ \dfrac{7}{5} } } dx \\  \\  \\ \displaystyle \longrightarrow  \tt\int  x {}^{ \dfrac{2}{5}  -  \dfrac{7}{5} } dx \\  \\  \\ \displaystyle \longrightarrow  \tt\int  x {}^{ \dfrac{ -5 }{5} } dx \\  \\  \\ \displaystyle \longrightarrow  \tt\int  x {}^{  \not\dfrac{ -5 }{5} } dx \\  \\  \\ \displaystyle \longrightarrow  \tt\int x {}^{ - 1} dx \\  \\  \\ \displaystyle \longrightarrow  \tt\int {\dfrac{1}{x} }dx \\  \\  \\   \displaystyle \longrightarrow\tt\red{in |x| +c}

Know to more :

  • Power rule.

\bull\tt \int x {}^{n} .dx \:  \rightarrow \:  \dfrac{x {}^{n + 1} }{n + 1}  + c

  • Multiplication by constant (c).

 \bull\tt \int c \: f(x).dx \:  \rightarrow \: c \int f(x).dx

  • Sum rule.

 \bull\tt \int (f + g)dx  \rightarrow \: \int fdx \:  +  \:  \int gdx

  • Difference rule.

\bull \tt \int (f - g)dx  \rightarrow \: \int fdx \:  - \:  \int gdx


Anonymous: Great..!!
TheBrainliestUser: A 1;)
Anonymous: Marvellous answer ✌
Anonymous: Great!!
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