Question

please give answer it's urgent​

Answer 1

Step-by-step explanation:

Ans (1) -4

Ans(2) 3

Ans (3) x-1=0 +1

1+1-3+2+1=. 2-1+1

+2 ans

Ans(4) 1x = 0.47.... _1

100x=4747.... _2

now, substrate _1 n _2

x = 47/99

Answer 2

Answer:

Q1= (-4)

Q2= (3)

Q3= (x^4-x^3-3x^2+2x+1) divided by (x-1)

x-1=0

x=1

1^4-1^3-3 (1)^2+2 (1)+1

1-1-3+3

0

remainder is 0

Q4= let x= 0.4777. (i)

multiple both sides by 10

10x= 10× 0.4777

10x =4.777. (ii)

subtract (i) and (ii)

10-x=4.777 - 0.4777

9x= 4.3

x =4.3/9

point 1 ke baad h

so ,

x=43/90

Q5(a)= 64x^3 -125y^3

(a^3-b^3)= (a-b)(a^2+b^2+ab)

(4x^3-5y^3) = (4x-5y) (4x^2+(-5y)^2+(4x) × (5y)^2

(4x-5y) (16x^2+25y^2-20xy)

Q5ka (b) 99^3

(100-1)^3

(a-b)^3= a^3-b^3-3a^2b+3ab^2

(100-1)^3=(100)^3-(1)^3-(100)^2×1+3×100×(1)^2

1000000 -1-30000+300

1000300-30001

970299

Q8= x^3+13x^2+32x+20

x^3+x^2+12x^2+12x+20x+20

x^2 (x+1)+12x (x+1) +20 (x+1)

(x+1) (x^2+12x+20)

(x^2+12x+20)

x^2+10x+2x+20

x (x+10)+2 (x+10)

(x+1)(x+10) (x+2)

hope its helpful

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