Question

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Answer 1

⬇⬇‼ ‼ HELLO ‼ ‼⬇⬇

✴ YOUR SOLUTION ⬇⬇⬇

✴Given,

✴The Product of digits of a no. is 35.

and when 18 is added to it the digit interchanged

✴Let x is at 10th place and Y unit place

✴the No. = 10x + y

✴X.Y = 35 -------(i)

✴10x + y + 18 = 10y + X

✴9x - 9y = -18

✴x - y = 2 --------(ii)

✴Putting value of x from eq. (I) into eq. (ii)

✴The polynomial become

y² + 2y - 35 =0

✴ Y² + 7y - 5y - 35 =0

✴ y(y + 7) -5(y - 7) =0

✴ Y = -7

✴ y = 5

✴ we have to choose Y=5 [ Digit cannot be Negative]

✴ X.Y= 35

✴ X = 7

✴ The no. become = (10×7) + 5 = 75

Answer 2

Step-by-step explanation:

Solve

let the number be at tens place is x

and at once place y

ATQ we have

xy=35

10y+x+18

digit are interchange they become 10x+y

=>9y-9x+18=0

=>y-x+2= 0

=>x=y+2

we have xy=35

(y+2)y=35

y²+2y-35=0

(y+7)(y-5)=0

y=-7 or 5

since digit cannot be negative

so,

y=5

therefore x=35/5 =7

two digits number 10y+x=10×5+7-5 ans

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