Question

Please give answer of II part of question no. 7​

Answer 1

Answer:

Step-by-step explanation:

the answer for II part of the 7th question

now

= 1/ √3 + √2

= multiply by √3 -√2 on both numerator and denometor

= √3-√2/ (√3 + √2) ( √3 - √2)

= √3 - √2 / 3 - 2

= √3 - √2

now take 2/√5 - √3

now mulliply by √5 +√3 on both numerator and denometor

= 2 x (√5 + √3 ) / (√5 - √3)(√5 + √3)

= 2(√5 + √3) / 5-3

= 2 ( √5+√3) /2

= √5 +√3

now take 3/√2 - √5

now multiply by √2+√5 on both numerator and denometor

= 3(√2+√5) / (√2-√5)(√2 + √5)

= 3 (√2+√5 ) / 2-5

= 3(√2+√5)/-3

= -(√2+√5)

now subsite this equation

= √3 - √2 - √5 -√3 + √2 + √5

= 0