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if the zeros of polynomial 1x2-2x-3 are half of the zeros of polynomial ax2+bx+c,then find the value of (a-b-c)
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it means that the roots of polynomial ax2+Bx+c should be twice the roots of x2-2x-3 .
roots of x2-2x-3 are (x+1)(x-3)=0 so -1 and 3.
roots of the new equation should be -2and 6 so new equation is
(x+2)(x-6)=x2-4x-12
so a=1,b=-4,c=-12
so a-b-c is 17
roots of x2-2x-3 are (x+1)(x-3)=0 so -1 and 3.
roots of the new equation should be -2and 6 so new equation is
(x+2)(x-6)=x2-4x-12
so a=1,b=-4,c=-12
so a-b-c is 17
nd bhumika bhat achi ha.. vo kisiko hurt nhi kar skti
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or tumha kya lagta ha. . love kya akk din me h ho jayga. , love is not a game
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OK,, main kuch nhi bolunga,,, but last time kam se kam byee to bol jaao,,,,,
bhumika,, please last baar baat kr jaao,,, sirf itta bol jao tumne aisa kyu kiya
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