Question

please give answer of these three questions​

Answer 1

Answer:

HOPE IT HELPFUL.

Step-by-step explanation:

I already answered the 4.4)a) question.

so here the other three questions,

4.4)b)

$\frac{3^{4}* 12^{3}*36 }{2^{5}*6^{3} } \\=\frac{81 * 1728 *36}{32 * 216} \\=\frac{81 * 1728}{32 *6} = \frac{81 * 288}{32} =\frac{81 *9}{1} \\=81 *9 = 729$

c)

$(\frac{6 *10 }{2^{2} *5^{3} } )^{2} * (\frac{25}{27}) \\=(\frac{2 *3*2*5}{2^{2}*5^{3} })^{2} * (\frac{5^{2} }{3^{3} })\\=( 2^{2-2} *3* 5^{1-3} )^{2} * (\frac{5^{2} }{3^{3} })\\=( 2^{0} * 3 *5^{-2})^{2} * (\frac{5^{2} }{3^{3} } )\\=(2^{0} *3^{2}*5^{4}) * (\frac{5^{2} }{3^{3} })\\= 2^{0}*3^{2-3}*5^{-4+2} = 1 *3^{-1}*5^{-2} \\=\frac{1}{30}$

4.5) I think the value of c is, $c= (\frac{n+2}{n+1} )$

( Im not sure )

4.6) The right answer of the question is,

$\frac{3^{5} }{9^{5} } = \frac{3^{5} }{(3^{2})^{5} } \\=3^{5-10} =3^{-5} =\frac{1}{3^{5} } =\frac{1}{243}$