Question

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Answer 1

Let A B C D be the given rhombus.

Where

BD= 16 cm

and

AC= 30 cm

We know that

Diagonals of rhombus are perpendicular bisector of each other

$od = bd \div 2$

$= 16 \div 2$

$= 8 \: cm$

$oa = ac \div 2$

$= 30 \div 2$

$= 15 \: cm$

Now,

In AOB, right angled at O

By Pythagoras Theorem

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