Question

please..... give answer of this trick.....

Answer 1

In the first circle we can have
64= a
5= b
and ? = c
so we can have that in all the circles
looking at the third circle I can make out that
63= 9*7
and 81 = 9²
so we can keep the unknown value as 7 ( to be supposed)
so we get an equation as
√a*b= c
on solving this for all four equations we the following values
1) √64*5=8*5=40
2) √49 *6= 7*6= 42
3) √81*b = 63
or 9b= 63
or b= 7
4) √a*4=20
or √a= 5
or a= 25