Question

please give answer please please I will mark answer as brainlist ​

Answer 1

Answer:

Step-by-step explanation:

2. given

p(x)=x^2-4x+3

p(2)=2^2-4*2+3=4-4+3=3

p(-1)=(-1)^2-4*-1+3=1+4+3=8

p(1/2)=(1/2)^2-4*1/2+3=1/4-2+3=1+1/4=5/4

=3-8+5/4=-5+5/4=5(-1+1/4)=5*(-3/4)=-15/4

3. P(x)=(x-2)^2-(x+2)^2=x^2+4-4x-x^2-4x-4=-8x

zeros of the polynomial is 0

4. zeros of the polynomial is 3x^3-2x^2-7x-2

if x=-1

3(-1)^3-2(-1)^2-7*-1-2

=-3-2+7-2

=-5+5=0

so

-1 is one of the zeros

(x+1) (3x^2-5x-2)

3x^2-5x-2=0

3x^2-6x+x-2=0 are two zeros of this polynomial

3x(x-2)+1(x-2)=0

x=2,-1/3