Question

please give answer questionno 25​

Answer 1

cos2x= cos60°cos30°+sin60°sin30°

cos2x= cos60°cos30°+(cos90°-60°)(cos90°-30°)

cos2x= cos60°cos30°+cos30°cos60°

cos2x= cos60°cos30°(1+1)

cos2x=( 1/2 ×√3/2 )2

cos2x=√3/2

cos2x= cos30°

x= 30°/2= 15°

Answer 2

Answer:

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