Math, asked by Astar01, 6 months ago

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Answered by chirag11082009
1

Step-by-step explanation:

Let ABCD be a quadrilateral whose diagonals bisect each other at right angles. Therefore, ΔAOB ≅ ΔCOB by SAS congruence condition. Opposites sides of a quadrilateral are equal hence ABCD is a parallelogram. Thus, ABCD is rhombus as it is a parallelogram whose diagonals intersect at right angle.

Answered by RECRUITS
0

Answer:

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