Question

please give answer quickly tomorrow is my exam

Answer 1

cotA+1/cotA = 2
squaring both side
(cotA+1/cotA)^2= 2^2
(cotA)^2+1/(cotA)^2+2*cotA*1/cotA= 4
(cotA)^2+1/(cotA)^2+ 2= 4
(cotA)^2+1/(cotA)^2= 4-2= 2 hope it helps u

Answer 2

ʜᴇʏᴀ!!

ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ

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ɢɪᴠᴇɴ , ᴄᴏᴛ ᴀ + 1 / ᴄᴏᴛ ᴀ = 2 

ᴏʀ , ( ᴄᴏᴛ ᴀ + 1 / ᴄᴏᴛ ᴀ )^2 = 2^2 [ sϙᴜᴀʀɪɴɢ ʙᴏᴛʜ sɪᴅᴇs ]

ᴏʀ , ( ᴄᴏᴛ ᴀ )^2 + 2 × ᴄᴏᴛ ᴀ × 1 / ᴄᴏᴛ ᴀ + ( 1 / ᴄᴏᴛ ᴀ )^2 = 4 

[ ★ ( ᴀ + ʙ )^2 = ᴀ^2 + 2ᴀʙ + ʙ^2 { ᴜsɪɴɢ ᴛʜɪs ɪᴅᴇɴᴛɪᴛʏ } ]

ᴏʀ , ᴄᴏᴛ^2 ᴀ + 1 / ᴄᴏᴛ^2 ᴀ  + 2 = 4

ᴏʀ , ᴄᴏᴛ^2 ᴀ + 1 / ᴄᴏᴛ^2 ᴀ = 4 - 2

ᴏʀ , ᴄᴏᴛ^2 ᴀ + 1 / ᴄᴏᴛ^2 ᴀ = 2      [ •°• ᴘʀᴏᴠᴇᴅ ]

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ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ! :)

★ ᴅᴇᴠɪʟ ᴋɪɴɢ