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ABC similar to STC by AA test ( angle C is common, angle B = angle T).
therefore AB/ST = BC/TC
therefore, p/x = (q+r)/r
p×r = x(q+r)
x = pr/(q+r)
therefore AB/ST = BC/TC
therefore, p/x = (q+r)/r
p×r = x(q+r)
x = pr/(q+r)
Answered by
1
By using Basic Proportionality theorem,
Which implies that,
So, it is expressed in terms of 'r', 'p' and 'q'.
Which implies that,
So, it is expressed in terms of 'r', 'p' and 'q'.
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