Question

please give answer this quwstion
i will mark him as brainliest​

Answer 1

☆ Given:-

• 5 resistors of $\large\sf\frac{1}{5}$ Ohm each.

☆ To Find:-

• Minimum Resistance.

☆ Now,

• We know that minimum resistance can be amde by combining all resistance in parallel.

• Also in parallel,

$\sf \mapsto \frac{1}{req} = \frac{1}{r1} + \frac{1}{r 2}.... \frac{1}{n}$

☆ So,

• Minimum Resistance,

$= \frac{1}{5} + \frac{1}{5} + \frac{1}{5} + \frac{1}{5} + \frac{1}{5} \\ \\ =\sf\cancel 5 \times ( \frac{1}{\cancel{5}}) ohm\\ \\ \sf\large\fbox\pink{ = 1 \: ohm }$

▪︎ Therefore the minimum resistance would be 1 Ohm.

☆ More about Resistances:-

• Maximum resistance can be made by combining it in series.

• In series Req = R1+R2...Rn.

• Resistance can be increased or decreased by using rehostat or resistance variable.

• The Potential Difference accross any resistor can be measured by voltmeter.

• Voltmeter is always connected in parallel to the resistors.