Math, asked by aaravgupta10, 1 year ago

please give answer to the question and explanation​

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Answered by hozefancc
1

Step-by-step explanation:

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Answered by 217him217
1

Step-by-step explanation:

=> [ (p+1/q)^(p-q) * (p-1/q)^(p+q) ]/ [ (q + 1/p)^(p-q) * (q-1/p)^(p+q) ] = (p/q)^x

=> [ (p+1/q)/(q+1/p)]^(p-q) * [ ( p-1/q)/(q-1/p) ]^(p-q) = (p/q)^x

=> [ ((pq+1)/q) /(pq+1)/p ]^(p-q) * [ ((pq-1)/q) /(pq-1)/p]^(p+q) = (p/q)^x

=> [ (1/q)/(1/p) ]^(p-q) * [ (1/q)/(1/p) ]^(p+q) = (p/q)^x

=> (p/q)^(p-q) * (p/q)^(p+q) = (p/q)^x

=> (p/q)^(p-q+p+q) = (p/q)^x

=> (p/q)^2p = (p/q)^x

=> x = 2p

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