please give answer tomorrow is my exam and of question paper
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Angle in semi circle = 90
DBC = 90
ACB = 90
= OBC + OBD
= OBC + 40
OBC = 50
BD║AC
OAC = 40
AOC = 70
ACD =70
DBC = 90
ACB = 90
= OBC + OBD
= OBC + 40
OBC = 50
BD║AC
OAC = 40
AOC = 70
ACD =70
jatin11:
thanks you very much bhai
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