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We know that on a straight line ,the sum of angles on one side is equal to 180°.
So,
(3x+7)°+(2x-19)°+x°=180°
3x+7+2x-19+x=180°
3x+2x+x+7-19=180°
6x-12=180°
6x=180°+12°
6x=192°
x=192°/6
[x=32°] answer///
Now ♪AOC=(3x+7)°
=3×32+7
=96+7
♪AOC=103°////)Answer
also,♪COD=(2x-19)°
=2×32-19
=64-19
♪COD =45°answer////
and ♪BOD=32°answer ///)
Hence,♪BOD=32°,√COD=45° and ♪AOC=103° .ANSWER ///
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