Question

please give answers fast and fast

Answer 1

area of octagonal surface=trapizium cdef+trapizium abgh+the oblong bcfg
=6/2(12+5)+6/2(12+5)+(12*5)=102+60=162m^2

Answer 2

Area of octagon is Area of trapezium CDEF + trapezium ABGH + rectangle BCGF
  =   2*Ar(CDEF)+Ar(ABGH)  (Since CDEF and ABGH have similar measures)
  =  [tex] 2( \frac{a+b}{2}*h)+2(l+b) = 2( \frac{a+b}{2}*h + (l+b)) = 2( \frac{5+12}{2}*6+(12+5)) [/tex]
  = 2(17*3+17)
  = 136