Question

Please give complete explanation

Answer 1

Let buoyant force be F.

Now F - m g = m g/6

Which gives F = 7mg/6

Let M be the mass of sand to be put to give acceleration g/6 down. Writing equation of motion, (m+M) g - F = (m+M)g/6

Putting value of F we get,

(m +M)g - 7mg/6 = (m+M) g/6

mg +Mg -7mg/6 =mg/6 + Mg/6

Mg(1–1/6) = mg (1/6+7/6–1)

Mg × 5/6 = mg ×2/6

M = 2mg/5

M = 2×5×10/5
= 20 kg

hope this helps you out!