Question

please give correct answer​

Answer 1

Answer:

1) In ∆ABP,

180° - (Angle ABP +angle APB) = angle BAP

180° - (60+90)° = angle BAP

30°= angle BAP

2) angle ABC = angle ACB = 60°

AB=AC (given)

angle APB =Angle APC ( right angles )

AP=AP (common )

therefore ∆APB is congruent to ∆APC ,

So, angle ABC = angle ACB = 60° by c.p.c.t.

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