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1) In ∆ABP,
180° - (Angle ABP +angle APB) = angle BAP
180° - (60+90)° = angle BAP
30°= angle BAP
2) angle ABC = angle ACB = 60°
AB=AC (given)
angle APB =Angle APC ( right angles )
AP=AP (common )
therefore ∆APB is congruent to ∆APC ,
So, angle ABC = angle ACB = 60° by c.p.c.t.
Hope it helps...
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