Question

please give correct answer​

Answer 1

Step-by-step explanation:

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Answer 2

$\large\bf{{\purple{{{\underline{\underline{Given:-}}}}}}}$

• cosec (90 - θ) - Sin(90 - θ) = 1
• (cosecθ - Sinθ) (tanθ + cotθ) = 1

$\large\bf{{\purple{{{\underline{\underline{To \: find:-}}}}}}}$

• We have to proof that both are equal to 1.

$\large\bf{{\purple{{{\underline{\underline{Formula \: used:-}}}}}}}$

• cosec 90⁰- θ = secθ
• sin 90⁰ - θ = cosθ

$\large\bf{{\purple{{{\underline{\underline{As \: we \: know:-}}}}}}}$

• secθ = 1/cosθ
• cosecθ = 1/sinθ

$\large\bf{{\purple{{{\underline{\underline{Step \: by \: step \: explaination:-}}}}}}}$

☯ Evaluating values in the given statement...

(secθ - cosθ)(cosecθ - sinθ)(sinθ/cosθ + cosθ/sinθ)

☯ Now calculating...

→ (1/cosθ - cosθ) (1/sinθ - sinθ) (sinθ/cosθ + cosθ/sinθ)

→ (1/cosθ - cosθ) (1/sinθ - sinθ) (sin²θ+cos²θ/ sinθ+cosθ)

→ (1 - cos²θ / cosθ) (1 - sin²θ) / sinθ) ( 1 / cosθ.sinθ)

☯ Now at last prooving...

→ (sin²θ / cosθ) (cos²θ / sinθ) ( 1 / cosθ.sinθ) = 1

Prooved✔️