Math, asked by deeparoy01051976, 1 month ago

please give correct answer​

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Answered by Anonymous
12

\footnotesize\boxed{  \underline{ \underline{\tt{ Solution:-}}}}  \: \purple \bigstar

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 \hline\begin{array}{ ||c|| }\purple \bigstar \:  \underline{\underline{\footnotesize \tt{Law  \: used:-}}} \\\footnotesize \tt{ {a}^{m}  \div  {a}^{n} = a ^{m - n}} \\\underline{\underline{ \footnotesize \tt{(\frac{a}{b})^{m}  =  \frac{ {a}^{m} }{ {b}^{m} }} }} \end{array}

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   \purple\dashrightarrow\tt{[( \frac{ - 1}{3} ) ^{8}  \div  (\frac{ - 1}{3} ) ^{5}]  - [( \frac{ - 1}{3} )^{5}  \div  (\frac{ - 1}{3} ) ^{3} ]}

\purple\dashrightarrow \tt{( \frac{ - 1}{3} ) ^{8 - 5}   - ( \frac{ - 1}{3} )^{5 - 3} }

\purple\dashrightarrow \tt{( \frac{ - 1}{3} ) ^{3}   - ( \frac{ - 1}{3} )^{2} }

\purple\dashrightarrow \tt{\frac{( - 1) \times ( - 1) \times ( - 1)}{3 \times 3 \times 3}    -  \frac{( - 1) \times  (- 1)}{3 \times 3}  }

\purple\dashrightarrow \tt{\frac{ - 1}{27}    -  \frac{1}{9}  }

\purple\dashrightarrow \tt{ \frac{ - 1 - 3}{27}    }

\footnotesize\boxed{\purple \dashrightarrow\underline{ \underline{\tt{ \frac{ -4}{27}}}}}  \: \purple \bigstar

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