Question

please give correct answer...any one who knows..as soon as possible​

Answer 1

Answer:

128

Step-by-step explanation:

Given A=$\left[\begin{array}{ccc}4&2&5\\2&0&3\\-1&1&0\end{array}\right]$

  then A⁻¹=$\left[\begin{array}{ccc}4&2&-1\\2&0&1\\5&3&0\end{array}\right]$

   AA⁻¹=$\left[\begin{array}{ccc}45&23&-2\\23&13&-2\\*-2&-2&2\end{array}\right]$

           =45(26-4)-23(46-4)-2(-46+26)

            =45(22)-23(42)+2(20)

            =64

2AA⁻¹=128

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