Math, asked by sunilsunil84679, 6 months ago

Please give correct answer with full explaination .​

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Answered by paridhimittal3106
1

Answer:

Rs. 2184

Step-by-step explanation:

For bigger box:

Length (l) = 25 cm,

Breadth (b) = 20 cm,

Height (h) = 5 cm

Total surface area of a box = 2(lb + bh + hl)

= 2[(25 x 20) + (20 x 5) + (5 x t25)] cm2

= 2 [500 + 100 + 125] cm2

= 2[725] cm2

= 1450 cm2

Total surface area of 250 boxes = (250 x 1450) cm2 = 362500 cm2

For smaller box:

l = 15 cm, b = 12 cm, h = 5 cm

Total surface area of a box = 2 [lb + bh + hl]

= 2[(15 x 12) + (12 x 5) + (5 x 15)] cm2

= 2[180 + 60 + 75] cm2 = 2[315] cm2 = 630 cm2

∴ Total surface area of 250 boxes = (250 x 630) cm2 = 157500 cm2

Now, total surface area of both type of boxes = 362500 cm2 +157500 cm2 = 520000 cm2 Area for overlaps = 5% of [total surface area]

= 5100 x 520000 cm2 = 26000 cm2

∴ Total surface area of the cardboard required = [Total surface area of 250 boxes of each type] + [Area for overlaps]

= 520000 cm2 + 26000 cm2 = 546000 cm2

∵ Cost of 1000 cm2 cardboard = Rs. 4

∴ Cost of 546000 cm2 cardboard

= Rs.4×5460001000 = Rs. 2184

Answered by Rajeshsatav826piya
5

Answer:

RS. 2184

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