please give correct answers
Attachments:
Answers
Answered by
1
I think we have to find the value of n and d. Because a value is already given.
Given First term a = 8
Given nth term l = 33
Given sn = 123.
We know that sum of n terms sn = n/2(a + l)
123 = n/2(8 + 33)
123 * 2 = n(41)
246 = 41n
n = 246/41
n = 6.
We know that last term l = a + (n - 1) * d
33 = 8 + (6 - 1) * d
33 = 8 + 5d
33 - 8 = 5d
25 = 5d
d = 5.
Hope this helps!
Given First term a = 8
Given nth term l = 33
Given sn = 123.
We know that sum of n terms sn = n/2(a + l)
123 = n/2(8 + 33)
123 * 2 = n(41)
246 = 41n
n = 246/41
n = 6.
We know that last term l = a + (n - 1) * d
33 = 8 + (6 - 1) * d
33 = 8 + 5d
33 - 8 = 5d
25 = 5d
d = 5.
Hope this helps!
Answered by
1
Hope it helps....
Please mark as brainliest....
Please mark as brainliest....
Attachments:
Similar questions
d = 12.5