Question

please give detailed explanation​

Answer 1

Join AO and CO

Tangent of a Circle is perpendicular to the radius at the point of contact

∠DAO=∠DCO=90°

In quadrilateral AOCD

∠D+∠A+∠O+90°=360°

50°+90°+∠O+90°=360°

Using central theorem

∠APC=360°-130°/2=115°

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