Please give detailed explanation with formula
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Answer:
AB∥CD and let EF and EG be the transversals.
Now, AB∥CD and EF is the transversal.
Then,
∠AEF=∠EFG [Alternate Angles]⇒y°=75°⇒y=75
Also,
∠EFC+∠EFD=180° [Since CFD is a straight line]⇒x+y=180⇒x+75=180⇒x=105
And,
∠EGF+∠EGD=180° [Since CFGD is a straight line]⇒∠EGF+125=180⇒∠EGF=55°
We know that the sum of angles of a triangle is 180°
∠EFG+∠GEF+∠EGF=180°⇒y+z+55=180⇒75+z+55=180⇒z=50∴x=105, y=75 and z=50
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