Question

please give explanation ​

Answer 1

Electric Field Intensity at the centre of a uniformly charged ring of radius R will be zero because of the following reason :

Let's consider any small segment of the ring with charge dQ . The electric field intensity at the centre due to that part will be :

$E1 = \dfrac{1}{4\pi \epsilon} \dfrac{dQ}{ {R}^{2} }$

Similarly there will be a diametrically opposite segment on the ring having a charge dQ giving equal and opposite Field intensity at the centre.

$E2 = \dfrac{1}{4\pi \epsilon} \dfrac{dQ}{ {R}^{2} }$

Now E1 and R2 are opposite and equal .

So if we see every elemental segment of the ring , there will be a diametrically opposite segment which will exert equal and opposite field intensity at the centre.

Hence net field intensity will be zero.

Answer 2

Answer:

Zero

Explanation:

if we consider a point charge dq at one side of the ring there will be field E=KQ/r²=Q/4π€•r²

at the opposite site of this there will be same electric field. so they will cancel out each other.

and it will become 0

as the ring is uniformly charged so, every where you imagine any point it will cancel out by the opposite side.

and electric field will be 0

hope it will help you.