Question

Please give fast answer

Answer 1

Answer:

Step-by-step explanation:

Heya User ,

--> cos a + sin a = √2 cos a

--> sin a = √2 cos a - cos a

=> sin a = ( √2 - 1 ) cos a

=> [ sin a / ( √2 - 1 ) ] = cos a

=> [ sin a ( √2 + 1 ) / ( 2 - 1 ) ] = cos a

0_0 --> We rationalized the denominator in the 2nd step ^_^  

=> [ √2 sin a + sin a ] = cos θa

=> cos a - sin a = √2 sin θ

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